- "Shop or die, people of Earth!"
- I don't see how doing shit like this can do anything but ensure massive failures in the 2016 elections.
- Nervous raccoon.
Today's main point is a continuation of thoughts on Ewoks from six years ago. Earlier this week, I saw this image in my RSS stuff:
And searching online for it again led me to this, which is an overly long discussion of a bunch of nonsense about how Endor would have been incinerated by the debris from the Death Star. After thinking about it for a few minutes, I came to the conclusion that that didn't make much sense, as pre-explosion, the DS had to have been moving sufficiently to not crash, so after the explosion, only a small fraction should hit the planet. Right?
So let's throw physics at the problem, and see. According to the Star Wars wiki page, Endor has a radius of 2450km radius. If it has the same average density as the Earth, this gives it a mass of 3.39e23 kg. We're trying to slam stuff into it, however, so let's go with an alternate calculation that the surface gravity is the same as on Earth (the Earth density Endor has about half-Earth gravity). This gives about twice the mass at 8.82e23 kg.
Now we know what the target looks like, but what about the DS? It apparently has a radius of 80km. What does that mean in terms of mass? No idea. It's made of "quadanium steel," so we have to make something up. Is it steel? That's 7.75 g/cm^3. Maybe quadanium makes it lighter, so maybe something like aluminum at 2.70 g/cm^3? Plus, a lot of the DS is empty, because otherwise you couldn't do stuff inside it. So there's a fill factor to deal with. Let's say all the rooms look like this one:
This one. |
Why? The DS blows up. It's a good "kablooey" kind of explosion. Assuming this is going to completely disperse all the mass to infinity, this means the explosion is comparable to the gravitational binding energy, U = 3/5 * GM^2 / R. For our 80km radius, and the high and low mass estimates give binding energies of 1.38e23 and 1.73e18 MJ. This has to be converted to kinetic energy of all the debris particles, so assuming equal mass, each particle gets, U = 1/2 (M/Np) * v^2, so v = sqrt(Np) * [129 7.67] km/s.
What's left to know? Where the DS is located in association to Endor. I remembered this scene:
Zap! |
This isn't a big deal, as I remembered that the DS is orbiting Endor because there's a shield generator that's protecting it. This means the DS has to be in a geostationary orbit. That wiki page for Endor claims it has a period of 18 hours. So the DS orbits at 18433km, and has an orbital velocity of 1.79km/s (which was yesterday's plot).
Put this all together, and run it through the N-body simulator to see what happens, and you get:
It freaking explodes. |
The other fun thing I tried was reducing the explosion strength by slowing the particle velocity:
Red is 100 times smaller and blue is a 1000. |
In these cases, the particles continue to largely follow the original DS orbit. In the lowest energy case, Endor is spared, and the extra energy goes to kicking particles out.
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